Determent Of The Tex Count Of Cotton Yarn By Using Warp Reel & Electric Balance

 Introduction: Count is a numerical experiment which defines fineness or corners of yarn. Count is a number indicating the mass per unit length or per unit mass.

There are two types of count

1. Direct
2. Indirect

Objects:

1. To know about yarn count
2. To calculate yarn fineness
3. To calculate yarn consumption
4. To maintain the buyer requirement 

Working principle: To know that Tex count is an direct count system. In an direct system the yarn number or count is the number of the units of weight per unit of length.

Tex Count: The weight of a fixed length 1000m of yarn is determined as the weight per unit length is the yarn count.

Nm =(W÷l)÷(w×l)

Where,

N =Count count

L    = Sample length

L   =Unit of length

W   =Unit of weight

W   =sample weight

Machine Description: In this experiment we saw that this machine contains more bobbin, one tension and yarn taker. The warp Reel is used to measure the length of yarn. This yarn is taker by a wheel where circum ference is 1.5 yds Electric balance is used to determine the weight of cotton yarn and we also use one bobbin carrier.

Warp Reel

Apparatus:

1. Bobbin carrier
2. Yarn package
3. Yarn tension
4. Handle
5. Wrap Reel
6. Electric balance
7. Steel bar 

Working Procedure: In this experiment at first we have taken a yarn package and put it on the bobbin carrier then. The yarn passed through the yarn tensioner to wrap reel then we start moving the handle wheel and it is moving 80 times then we found our desired one then we complete the calculate and found the count CV% controlling working action etc. Before calculation we weight the desired yarn finally. By this value we draw the graph of control limit.

Calculation: From table 1 count N

We know that Nm =(sample weight ÷weight unit ) × (length unit × samplelength)

So ,

Nm1 = (2.12gm÷1gm) × (1000m÷120yds)

          =(2.12) × (1000 ÷109.68) = 19.32

Nm2 =(2.10) × (1000 ÷109.68) = 19.15

Nm3 =(2.16) × (1000 ÷109.68) = 19.69

Nm4 =(2.08) × (1000 ÷109.68) = 19.96

Nm5 =(2.114) × (1000 ÷109.68) = 19.51

Average count: =19

From table 2:- SD = 0.25

Table 01:- Table for average count

Obs no	Sample length	Length unit	Sample weight	Weight count	Count	Average count
1	120	1000m	2.12	1gm	19.32	19.30=19
2	120	1000m	2.10	1gm	19.15
3	120	1000m	2.16	1gm	19.59
4	120	1000m,	2.08	1gm	18.96
5	120	1000m	2.14	1gm	19.51

Table 2:-Table for efficient of variation

Obs no	count	Average count	(Xi-X)2	SD	CV%
1	19.32	19.30	0.01	0.25	1.295
2	19.15		o.02
3	19.59		0.08
4	18.96		0.12
5	19.51		0.04

Table 3:- table for controlling Value

UCL	UWAL	CL	LWAL	LCL
32.08	27.72	19	10.28	5.92

Result: The selected cotton yarn is= 19 and the value of co-officient variation is 1.295%

Remarks: In this experiment we know about the Tex count system and it is very helpful in our working life and to be a good textile engineer, we must know it very well.

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