Determent Of The Matric Count Of Cotton Yarn By Using Warp Reel & Electric Balance

Introduction: Count is a numerical experiment which defines fineness or corners of yarn. Count is a number indicating the mass per unit length or per unit mass.

There are two types of count

1. Direct
2. Indirect

Objects:

• To know about yarn count
• To calculate yarn fineness
• To calculate yarn consumption
• To maintain the buyer requirement

Working principle: To know that matric count is an indirect count system. In an indirect system the yarn number or count is the number of the units of length per unit of weight.

Matric count: The number of lea of 1000m of yarn present in 1 kg of yarn is known as matric count and denoted by Nm. So mathematically

Nm =(L×w)÷(l×W)

Where,

Nm =Count

L    = Sample length

L   =Unit of length

W   =Unit of weight

W   =sample weight

Machine Description: In this experiment we saw that this machine contains more bobbin, one tension and yarn taker. The warp Reel is used to measure the length of yarn. This yarn is taker by a wheel where circumference is 1.5 yds Electric balance is used to determine the weight of cotton yarn and we also use one bobbin carrier.

Warp Reel

Apparatus:

1. Bobbin carrier
2. Yarn package
3. Yarn tension
4. Handle
5. Wrap Reel
6. Electric balance
7. Steel bar

Working Procedure: In this experiment at first we have taken a yarn package and put it on the bobbin carrier then. The yarn passed through the yarn tensioner to wrap reel then we start moving the handle wheel and it is moving 80 times then we found our desired one then we complete the calculate and found the count CV% controlling working action etc. Before calculation we weight the desired yarn finally. By this value we draw the graph of control limit.

Calculation: From table 1 count N

We know that, Nm =(sample length ÷ unit of length) × (unit of weight × sample weight)

So ,

Nm1 = (120yds÷1000m) × (1kg ÷ 2.12gm)

          =(109.2 ÷1000) × (1000 ÷2.12) = 52.72

Nm2 =(109.2 ÷1000) × (1000 ÷2.10) = 52.22

Nm3 =(109.2 ÷1000) × (1000 ÷2.16) = 50.77

Nm4 =(109.2 ÷1000) × (1000 ÷2.08) = 52.70

Nm5 = (109.2 ÷1000) × (1000 ÷2.14) = 51.25

Average count: =51

From table 2:- SD = 0.76

CV% = 1.46%

CL = 51

UCL = 72.42

LCL = 29.57

UWAL = 65.28

LWAL = 36.71

Table 01:- Table for average count

Obs no	Sample length	Length unit	Sample weight	Weight count	Count	Average count
1	120	1000m	2.12	1000gm	51.74	51.73
2	120	1000m	2.10	1000gm	52.22
3	120	1000m	2.16	1000gm	50.77
4	120	1000m,	2.08	1000gm	52.70
5	120	1000m	2.14	1000gm	51.25

Table 2:-Table for efficient of variation

Obs no	count	Average count	(Xi-X)2	SD	CV%
1	51.74	51.73	0.01	0.76	1.46
2	52.22		o.24
3	50.77		0.921
4	52.70		0.94
5	51.25		0.23

Table 3:- table for controlling Value

UCL	UWAL	CL	LWAL	LCL
72.42	65.28	51	65.28	29.57

Result: The selected cotton yarn is 76 and the value of co-officient variation is 1.17%

Remarks: In this experiment we know about the matric count system and it is helpful in our working life and to be a good textile engineer, we must know it very well.

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